作业帮帮我用lingo编编程吧设X1,X2,X3……X46为46档长度肠衣分别的数,N成品捆数.则 Max Z＝N （成品捆数越多越好）89.5>=3X1+3.5X2+……+6.5X8>=88.589.5>=7X9+7.5X10+……+13.5X22>＝88.589.5>=14X23+14.5X24+……+25.5X46＝>88
来源：学生作业帮助网 编辑：作业帮 时间：2024/05/11 20:10:11
帮我用lingo编编程吧设X1,X2,X3……X46为46档长度肠衣分别的数,N成品捆数.则 Max Z＝N （成品捆数越多越好）89.5>=3X1+3.5X2+……+6.5X8>=88.589.5>=7X9+7.5X10+……+13.5X22>＝88.589.5>=14X23+14.5X24+……+25.5X46＝>88
帮我用lingo编编程吧
设X1,X2,X3……X46为46档长度肠衣分别的数,N成品捆数.
则 Max Z＝N （成品捆数越多越好）
89.5>=3X1+3.5X2+……+6.5X8>=88.5
89.5>=7X9+7.5X10+……+13.5X22>＝88.5
89.5>=14X23+14.5X24+……+25.5X46＝>88.5
X1+X2+……+X8＝19N
X9+X10+……+X22＝7N
X23+X24+……+X46＝4N
帮我把这个编编程吧!
帮我用lingo编编程吧设X1,X2,X3……X46为46档长度肠衣分别的数,N成品捆数.则 Max Z＝N （成品捆数越多越好）89.5>=3X1+3.5X2+……+6.5X8>=88.589.5>=7X9+7.5X10+……+13.5X22>＝88.589.5>=14X23+14.5X24+……+25.5X46＝>88
model:
sets:
set1/1..46/:X;
endsets
ub=89.5;
lb=88.5;
max = N;
@sum(set1(i)|i#ge#1 #and# i#le#8:X(i))=19*N;
@sum(set1(i)|i#ge#9 #and# i#le#22:X(i))=7*N;
@sum(set1(i)|i#ge#23 #and# i#le#46:X(i))=4*N;
@sum(set1(i)|i#ge#1 #and# i#le#8:(3+0.5*(i-1))*X(i))=lb;
@sum(set1(i)|i#ge#9 #and# i#le#22:(7+0.5*(i-9))*X(i))=lb;
@sum(set1(i)|i#ge#23 #and# i#le#46:(14+0.5*(i-23))*X(i))=lb;
end
如果需要整数要求,则需要加上@for(set1(i):@gin(X));