y=sin^2(2x)+4sin^4(x)的最小正周期是

证明sinx+siny+sinz-sin(x+y+z)=4sin((x+y)/2)sin((x+y)/2)sin((x+y)/2) 傅里叶级数作图f（x）=2sin[x] - sin[2x] + 2/3sin[3x] - 1/2sin[4x]我用mathematica输入程序Plot[{2sin[x],-2sin[x],2sin[x] - sin[2x],-2sin[x] + sin[2x],2sin[x] - sin[2x] + 2/3sin[3x],-2sin[x] + sin[2x] - 2/3sin[3x],2sin[x] - sin[2x] + 2/3si y=sin^2(2x)+4sin^4(x)的最小正周期是 y=sin^2（2x）+4sin^4（x）的周期 2sin(x+π/4)sin(x-π/4)=? y=[sin^2(x)]*[sin^2(x)]求导 一道三角恒等式证明题请证明sin(x+y)sin(x-y)=sin^2(x)-sin^2(y) 函数y=cos^4x-sin^4x的最小正周期y=(cos^2x+sin^2x)(cos^2x-sin^2x)为什么等于cos^2x-sin^2x=cos2x谢谢 y=(sin x + COS x)^2 y=sin^4x+cos^4x=(sin^2x+cos^2x)^2-2sin^2xcos^2x 这一步是怎么来的? 求大牛帮忙写一个matlab 画图 Y=(sin(x))^2/x/x*sin(4x)^2 6-4x-x^2=5/|sin(y/x)cos(y/x)|的解 s = 2*sin(x)-sin(2*x)+2/3*sin(3*x)-1/2*sin(4*x)+2/5*sin(5*x)用matlab画图,求教啊 证明一个sin&cos的等式证明 1+sin^2(x)+sin^4(x)+sin^6(x)=[1-sin^8(x)]/[cos^2(x)] 化简sin^4x-sin^2x+cos^2x 化简:sin^4 x-sin^2 x+cos^2 x 求y=sin[sin(x^2)]的导数 y=|sin(2x+π/4)|+2的周期