数列{an}满足递推式an=3a(n-1)+3^n-1(n>=2),又a1=5,求数列{an}的通项公式

数列[An]满足a1=2,a（n+1）=3an-2 求an 数列{an}满足递推式an=3a(n-1)+3^n-1(n>=2),又a1=5,求数列{an}的通项公式 已知数列an满足a1=1,a(n+1)=an/(3an+1) 求数列通项公式 数列{an)满足an=4a(n-1)+3,a1=0,求数列{an}的通项公式 已知数列an满足a1=1,a(n+1)=an/(3an+2),则an=? 数列{An}满足A1=1,A(n+3)=An+3,A（n+2)=An +2 已知数列{an}满足a(n+1)=an+n,a1=1,则an= 数列{an}满足a1=2,a(n+1)=2an+n+2,求an 数列｛an｝满足a1=1,且an=an-1+3n-2,求an 在数列an中,a1=1,且满足a（n+1）=3an +2n,求an 已知数列｛an｝满足a(n+1)=an+3n+2,且a1=2,求an=? 已知数列an满足a(n+1)=an+3n+2,且a1=2,求an 数列{an}满足a0是常数,an=3(n-1)-2a(n-1),求an 数列｛an｝满足a1=3,a n+1=2an,则a4等于 已知数列{an}满足a1=1,3a(n+1)+an-7 数列｛an｝满足lim(an+1-an)=a,证明liman/n=a 求一道很简单的数列题数列｛a｝满足an=（n^2+n+1)/3求an+1 已知数列{an}满足:a1=1,a(n+1)=3an/(an+3),an不等于0.(n属于自然数)猜想{an}的通项公式