3a-3b/10ab*25a^b3/a^-b^= x^-4y^/x^+2xy+y^/x+2y/2x^+2xy(3a-3b)/(10ab)*(25a^b3)/(a^-b^)= (x^-4y^)/(x^+2xy+y^)/(x+2y)/(2x^+2xy)=

来源:学生作业帮助网 编辑:作业帮 时间:2024/05/19 08:39:41
3a-3b/10ab*25a^b3/a^-b^= x^-4y^/x^+2xy+y^/x+2y/2x^+2xy(3a-3b)/(10ab)*(25a^b3)/(a^-b^)= (x^-4y^)/(x^+2xy+y^)/(x+2y)/(2x^+2xy)=

3a-3b/10ab*25a^b3/a^-b^= x^-4y^/x^+2xy+y^/x+2y/2x^+2xy(3a-3b)/(10ab)*(25a^b3)/(a^-b^)= (x^-4y^)/(x^+2xy+y^)/(x+2y)/(2x^+2xy)=
3a-3b/10ab*25a^b3/a^-b^= x^-4y^/x^+2xy+y^/x+2y/2x^+2xy
(3a-3b)/(10ab)*(25a^b3)/(a^-b^)=
(x^-4y^)/(x^+2xy+y^)/(x+2y)/(2x^+2xy)=

3a-3b/10ab*25a^b3/a^-b^= x^-4y^/x^+2xy+y^/x+2y/2x^+2xy(3a-3b)/(10ab)*(25a^b3)/(a^-b^)= (x^-4y^)/(x^+2xy+y^)/(x+2y)/(2x^+2xy)=
1.
=3(a-b)/(10ab)*(25a^2 b^3)/((a+b)(a-b))
=15/2*(a b^2)/(a+b)
2.
=(x+2y)(x-2y)/(x+y)^2*2x(x+y)/(x+2y)
=2x(x-2y)/(x+y)

请问你要干什么,解答,请详细说明

可以适当的加些括号,要不然看起来实在是混乱,还有容易让人误解。

886