作业帮若a=1/3(1g16+log5(25)-1g1/5)-1g0.2,b=(1g2)^2+1g2*1g25+(1g5)^2,则a减b等于( )A -1 B 0 C 1 D 2但为什么?
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若a=1/3(1g16+log5(25)-1g1/5)-1g0.2,b=(1g2)^2+1g2*1g25+(1g5)^2,则a减b等于( )A -1 B 0 C 1 D 2但为什么?
若a=1/3(1g16+log5(25)-1g1/5)-1g0.2,b=(1g2)^2+1g2*1g25+(1g5)^2,则a减b等于( )
A -1 B 0 C 1 D 2
但为什么?
若a=1/3(1g16+log5(25)-1g1/5)-1g0.2,b=(1g2)^2+1g2*1g25+(1g5)^2,则a减b等于( )A -1 B 0 C 1 D 2但为什么?
a=1/3(4lg2+log5(5^2)+lg5)-lg(5^-1)=1/3(3lg2+2+lg5+lg2)+lg5=1/3(3lg2+2+lg10)+lg5=lg2+1+lg5=2; b=(lg2+lg5)^2=1^2=1;所以2-1=1
a=1/3(1g16+log5(25)-1g1/5)-1g0.2
=1/3(lg16/0.2+lg100)-lg0.2
=1/3lg8000-lg0.2
=lg20/0.2
=2
b=(1g2)^2+1g2*1g25+(1g5)^2
=(lg2)^2+2lg2lg5+(lg5)^2
=(lg2+lg5)^2
=(lg2x5)^2
=1
所以：a-b=1 故选C
若a=1/3(1g16+log5(25)-1g1/5)-1g0.2,b=(1g2)^2+1g2*1g25+(1g5)^2,则a减b等于( )A -1 B 0 C 1 D 2但为什么?
log5 2+log5 3+log5 1/6=?
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