f(x)=√2sin(2x+π/3) 求f(-x)的单调增区间

f(x)=√2sin(2x+π/3) 求f(-x)的单调增区间
f(x)=√2sin(2x+π/3) 求f(-x)的单调增区间

f(x)=√2sin(2x+π/3) 求f(-x)的单调增区间
f(-x)=√2sin(-2x+π/3)=√2cos(π/2+2x-π/3)=√2cos(2x-π/6)
f(x)=√2cos(2x-π/6)的减区间
就是f(-x)的增区间
所以0