已知|a-1/2|+(b+2)^2=0求a^3-3a^2b+4ab^2-2b^2

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已知|a-1/2|+(b+2)^2=0求a^3-3a^2b+4ab^2-2b^2

已知|a-1/2|+(b+2)^2=0求a^3-3a^2b+4ab^2-2b^2
已知|a-1/2|+(b+2)^2=0求a^3-3a^2b+4ab^2-2b^2

已知|a-1/2|+(b+2)^2=0求a^3-3a^2b+4ab^2-2b^2
|a-1/2|+(b+2)^2=0
|a-1/2|>=0
(b+2)^2>=0
所以
|a-1/2|=0
(b+2)^2=0
a=1/2
b=-2
a^3-3a^2b+4ab^2-2b^2
=(a-b)^3+ab^2-b^2
=125/8-2+4
=141/8