1.（ab+1)^2-(ab-1)^22.(3mn+1)(3mn-1)-8m^2n^23.(x+2)^2-(x+5)(x-1)4.(x-2)^2-2(x+1)(x-1)5.(x+2)^2-(3x+1)(x-1)6.(-2a+10b)(2a+10b)

来源：学生作业帮助网编辑：作业帮时间：2024/05/08 21:21:20

1.（ab+1)^2-(ab-1)^22.(3mn+1)(3mn-1)-8m^2n^23.(x+2)^2-(x+5)(x-1)4.(x-2)^2-2(x+1)(x-1)5.(x+2)^2-(3x+1)(x-1)6.(-2a+10b)(2a+10b)
1.（ab+1)^2-(ab-1)^2
2.(3mn+1)(3mn-1)-8m^2n^2
3.(x+2)^2-(x+5)(x-1)
4.(x-2)^2-2(x+1)(x-1)
5.(x+2)^2-(3x+1)(x-1)
6.(-2a+10b)(2a+10b)

1.（ab+1)^2-(ab-1)^22.(3mn+1)(3mn-1)-8m^2n^23.(x+2)^2-(x+5)(x-1)4.(x-2)^2-2(x+1)(x-1)5.(x+2)^2-(3x+1)(x-1)6.(-2a+10b)(2a+10b)
1.（ab+1)^2-(ab-1)^2
=(ab+1+ab-1)(ab+1-ab+1)=4ab
2.(3mn+1)(3mn-1)-8m^2n^2
=9m^2n^2-1-8m^2n^2
=m^2n^2-1
3.(x+2)^2-(x+5)(x-1)
=x^2+4x+4-x^2-4x+5
=9
4.(x-2)^2-2(x+1)(x-1)
=x^2-4x+4-2x^2+1
=-x^2-4x+5
=(x+5)(1-x)
5.(x+2)^2-(3x+1)(x-1)
=x^2+4x+4-3x^2+2x+1
=-2x^2+6x+5
6.(-2a+10b)(2a+10b)
=100b^2-4a^2

1.(ab+1)^2-(ab-1)^2
=(ab+1+ab-1)(ab+1-ab+1)
=2ab*2
=4ab
2.(3mn+1)(3mn-1)-8m^2n^2
=9m^2n^2-1-8m^2n^2
=m^2n^2-1
3. 分太少.

1、原式=（ab+1+ab-1）*(ab+1-ab+1)=2ab
2、=9m^2n^2-1-8m^2n^2=m^2n^2-1
都是用公式好吧，回去慢慢算阿！

1=aabb+1+2ab-aabb-1+2ab=4ab
2=9mmnn-1-8mmnn=mmnn-1
3=xx+4+4x-xx+4x-5=8x-1
4=xx+4-4x--2xx+2=-xx-4x+6
5=xx+4x+4-3xx+2x-1=-2xx+6x+3
6=(10b-2a)(10b+2a)=100bb-4aa

5ab-2[3ab-(4ab²+2分之1ab)]-5ab² (2/3ab^2-2ab)*1/2ab (2/3ab^2-2ab)×1/2ab (ab+1)2-(ab-1)2为什么会等于(ab+1+ab-1)(ab+1-ab+1) 1.多项式2ab-ab的平方+3与2ab的平方+3ab-1的差为（）. ab【(ab+1)(ab-1)】²,因式分解 (1)ab 计算(ab+1)(ab-1)-(1-ab)(-ab-1) 2(a²b+ab)-2(ab²-1)-2ab²-2ab 化简就行了 ab-[3ab-(4ab^2+1)]-4ab^2化简.（要有过程） ab-[3ab-(4ab^2+1)]-4ab^2化简. 已知a-b=,ab=1/8,求-2ab+ab+ab的值 1.(-4ab^3)(-8/1ab)-(2/1ab^2）^2.^的意思的次方.(-4ab的3次方）（-8分之1ab)-(2分之1ab的2次方）的2次方,等于多少? 已知（a-2）+（b+1）=0,求多项式3ab+ab-3ab+5ab+ab+2分之1ab 已知a-b=5,ab=-1,求代数式（22a+3b-2ab)-(a+4b+ab)-(3ab+2b-2a)的值. （-1/2ab)*(a^2-2ab-1）因式分解因式分解:(a^2b^2+ab)^2-(ab+1)^2 -1/2ab^2(b^2+3ab^2)计算