已知|x+2|+(y+3)²=0,求6xy²-[3x²y-(2x²y-xy²)]的值.

来源:学生作业帮助网 编辑:作业帮 时间:2024/05/03 19:48:59
已知|x+2|+(y+3)²=0,求6xy²-[3x²y-(2x²y-xy²)]的值.

已知|x+2|+(y+3)²=0,求6xy²-[3x²y-(2x²y-xy²)]的值.
已知|x+2|+(y+3)²=0,求6xy²-[3x²y-(2x²y-xy²)]的值.

已知|x+2|+(y+3)²=0,求6xy²-[3x²y-(2x²y-xy²)]的值.

x=-2 y=-3
6xy²-3x²y+2x²y-xy²
=-x²y+5xy²
=xy(-x+5y)
=-78