(x^2-2x)(x^2-2x-2)-3x^4-8x^2y^2+16y^4+(2a+b)^2= =第二题不用了

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(x^2-2x)(x^2-2x-2)-3x^4-8x^2y^2+16y^4+(2a+b)^2= =第二题不用了

(x^2-2x)(x^2-2x-2)-3x^4-8x^2y^2+16y^4+(2a+b)^2= =第二题不用了
(x^2-2x)(x^2-2x-2)-3
x^4-8x^2y^2+16y^4+(2a+b)^2
= =第二题不用了

(x^2-2x)(x^2-2x-2)-3x^4-8x^2y^2+16y^4+(2a+b)^2= =第二题不用了
(1)原式=(x^2-2x)(x^2-2x)-2(x^2-2x)-3
=[x(x-2)]^2-2x(x-2)-3
=([x(x-2)-3][x(x-2)+1]
=(x^2-2x-3)(x^2-2x+1)
=(x-3)(x+1)(x-1)^2
(2)原式=(x^2-4y^2)^2+(2a+b)^2
=([(x-2y)(x+2y)]^2+(2a+b)^2
可能你题有错,后面2a+b若为2x+y则
原式=(2x+y)^2[(x-2y)^2+1]

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