计算[-(1/2a²x)²+(1/3ax²×ax)]÷(1/6ax)

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计算[-(1/2a²x)²+(1/3ax²×ax)]÷(1/6ax)

计算[-(1/2a²x)²+(1/3ax²×ax)]÷(1/6ax)
计算[-(1/2a²x)²+(1/3ax²×ax)]÷(1/6ax)

计算[-(1/2a²x)²+(1/3ax²×ax)]÷(1/6ax)
[-(1/2a²x)²+(1/3ax²×ax)]÷(1/6ax)
=(-1/4a^4·x^2+1/3a^2·x^3)÷(1/6ax)
=-3/2a^3·x+2a·x^2