记n!=n(n-1)(n-2).……3.2.1,则2/3!+3/4!+4/5!+……+99/100!为

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记n!=n(n-1)(n-2).……3.2.1,则2/3!+3/4!+4/5!+……+99/100!为

记n!=n(n-1)(n-2).……3.2.1,则2/3!+3/4!+4/5!+……+99/100!为
记n!=n(n-1)(n-2).……3.2.1,则2/3!+3/4!+4/5!+……+99/100!为

记n!=n(n-1)(n-2).……3.2.1,则2/3!+3/4!+4/5!+……+99/100!为
2/3!+3/4!+4/5!+……+99/100!
= (3-1)/3!+(4-1)/4!+(5-1)/5!+……+(100-1)/100!
=3/3!-1/3!+4/4!-1/4!+5/5!-1/5!+.+100/100!-1/100!
=1/2!-1/3!+1/3!-1/4!+1/4!-1/5!+.+1/99!-1/100!
=1/2!-1/100!
=1/2-1/100!

e^(1/n)+e^(2/n)+e^(3/n)+…+e^(n-1/n)+e^(n/n)=? 数学不等式证明题n=1,2,……证明:(1/n)^n+(1/2)^n+……+(n/n)^n第二个是(2/n)^n 设f(n)=1/n+1+1/n+2+1/n+3+……+1/3n(n∈N+),则f(n+1)-f(n)=? 组合:C(n,0)+C(n,1)+……+C(n,n)=n^2 lim(1/n+2/n+3/n+4/n+5/n+……+n/n)=lim(1/n)+lim(2/n)+……+lim(n/n)成立吗?(n趋近于无穷大)为什么不成立? 证明C(0,n)^2+C(1,n)^2+……+C(n,n)^2=C(n,2n) 用数学归纳法证明(n+1)+(n+2)+……+(n+n)=n(3n+1)/2 lim(n→∞) (1/n)[sin(π/n)+sin(2π/n)+…+sin(nπ/n)]=? lim (n/(n²+1)+n/(n²+2²)+…………+n/(n²+n²))=?n趋向无穷大 (n+1)*n/2+n*(n-1)/2+(n-1)*(n-2)/2+(n-2)*(n-3)/2+……3*2/2+2*1/2=? 用数学归纳法证明(n+1)(n+2)…(n+n)=2^n*1*3*…*(2n-1)(n∈N+)不是左边多什么 用数学归纳法证明:1*n+2(n-1)+3(n-2)+…+(n-1)*2+n*1=(1/6)n(n+1)(n+2) 设f(n)=1/n+1+1/n+2+…+1/2n(n属于N*),那么f(n+1)-f(n)= 证明(1/n)^n+(2/n)^n+……+(n-1/n)^n > (n-1)/2(n+1) 对任意n正整数成立 1.2/n(n+1)(n+2)2.n(n+1)(n+2)3.n(n+1)4,∑k3=1^3+2^3+……n^3= (1/(n^2 n 1 ) 2/(n^2 n 2) 3/(n^2 n 3) ……n/(n^2 n n)) 当N越于无穷大的极限(1/(n^2+n+1 ) +2/(n^2+n+2) +3/(n^2+n+3) ……n/(n^2+n+n)) 当N越于无穷大的极限 定义数列{An}:A1=3/2,An={1.A(n-1)+n-1 n为奇数 2.3A(n-1) n为偶数 1.求A2.A3.A4的值 2.记Bn=A(2n-1)+n+0.5,n属于N*.求证:数列{Bn}是等比数列 3.记S(2n)=A1+A2+…+A(2n-1)+A(2n),试比较S2(n+1) + 3 / 3^(n+1) 与 S(2n) + f(n)=1/(n+1)+1/(n+2)+1/(n+3)……+1/2n (n∈N*),f(n+1f(n)=1/(n+1)+1/(n+2)+1/(n+3)……+1/2n (n∈N*),f(n+1)-f(n)=?