如图,AB=AC,AD=AE,BD=CE,BD与CE相交与O.求证:∠CAB=∠EAD=∠BOD.∠CAB=∠EAD=∠BOC

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如图,AB=AC,AD=AE,BD=CE,BD与CE相交与O.求证:∠CAB=∠EAD=∠BOD.∠CAB=∠EAD=∠BOC

如图,AB=AC,AD=AE,BD=CE,BD与CE相交与O.求证:∠CAB=∠EAD=∠BOD.∠CAB=∠EAD=∠BOC
如图,AB=AC,AD=AE,BD=CE,BD与CE相交与O.求证:∠CAB=∠EAD=∠BOD.

∠CAB=∠EAD=∠BOC

如图,AB=AC,AD=AE,BD=CE,BD与CE相交与O.求证:∠CAB=∠EAD=∠BOD.∠CAB=∠EAD=∠BOC
AB=AC,AD=AE,BD=CE
三角形ABD全等于三角形ACE
所以∠DAB=∠CAE,DBA=ECA
DAE=CAE-DAC=DAB-DAC=BAC
OFC=AFB,DBA=ECA=》BOE=BAC

∠BOD. 是平角啊