若lim(n→∞)[(n^3-1)/(n^2-3n+1)+an+b]=1,则a+b=?

lim (n!+(n-1)!+(n-2)!+(N-3)!+⋯..+2!+1)/n!其中n→∞ 求lim n→∞ (1+2/n)^n+3 lim(n→∞)[1-(2n/n+3)] lim(n→∞)(2n-1/n+3) lim(n→∞)[1/(3n+1)+1/(3n+2)+~1/(3n+n)] 求极限lim [ 2^(n+1)+3^(n+1)]/2^n+3^n (n→∞) lim（n→∞）(3n^3-2n+1)/n^3+n^2 快 计算lim(n→∞)(1^n+2^n+3^n)^(1/n) lim n →∞ (1^n+3^n+2^n)^1/n,求数列极限 求极限lim(x→∞)（1/n+2/n+3/n..+n/n） lim n→∞ (n+2)^3+(2n+3)^3/(n-1)(2n-1)(3n-2) 是多少? lim(n→∞) 1/(n+1)-2/(n+1)+3/(n+1)-4/(n+1)+...+[(2n-1)/(n+1)]-[(2n)/(n-1)]求极限 用数列极限证明lim(n→∞)(n^-2)/(n^+n+1)=1中证明如下:lim(n→∞)3n+1/5n-4 lim（n→∞) （(2n!/n!*n)^1/n的极限用定积分求是lim（n→∞) 1/n(2n!/n!)^1/n 不好意思 求极限lim(-2)^n+3^n/(-2)^[n+1]+3^[n+1] (x→∞) 求lim(n→∞)(3n^3+2n^2+1)/(2n^2+3) lim n→∞ n^(3/2)* (n+1)^(1/2)* (1-cos(π/n))=? 大学微积分的题目 lim(x→∞)(1^n+2^n+3^n)^1/n