作业帮已知2x+y=4,求代数式[(x+y)²-(x-y)²-2y(x-1/2y)]÷4y的值 （还没学因式分解）
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![已知2x+y=4,求代数式[(x+y)²-(x-y)²-2y(x-1/2y)]÷4y的值 （还没学因式分解）](/uploads/image/z/2536340-68-0.jpg?t=%E5%B7%B2%E7%9F%A52x%2By%3D4%2C%E6%B1%82%E4%BB%A3%E6%95%B0%E5%BC%8F%5B%28x%2By%29%26%23178%3B-%28x-y%29%26%23178%3B-2y%28x-1%2F2y%29%5D%C3%B74y%E7%9A%84%E5%80%BC+%EF%BC%88%E8%BF%98%E6%B2%A1%E5%AD%A6%E5%9B%A0%E5%BC%8F%E5%88%86%E8%A7%A3%EF%BC%89)
已知2x+y=4,求代数式[(x+y)²-(x-y)²-2y(x-1/2y)]÷4y的值 （还没学因式分解）
已知2x+y=4,求代数式[(x+y)²-(x-y)²-2y(x-1/2y)]÷4y的值 （还没学因式分解）
已知2x+y=4,求代数式[(x+y)²-(x-y)²-2y(x-1/2y)]÷4y的值 （还没学因式分解）
[(x+y)²-(x-y)²-2y(x-1/2y)]÷4y=[(x²+2xy+y²)-(x²-2xy+y²)-2xy+y²]÷4y=(2xy+y²)÷4y=y(2x+y)÷4y
=4/4=1
[(x+y)²-(x-y)²-2y(x-1/2y)]÷4y
=[(x²+2xy+y²)-(x²-2xy+y²)-2xy+y²]÷4y
=(2xy+y²)÷4y
=y(2x+y)÷4y
=4/4
=1