阅读下面例题:解方程x²-x的绝对值-2=0 (1)当x≥0时,原方程化为:x²-x的绝对值-2=0(1)当x≥0时,原方程化为x2-x-2=0,解得:x1=2,x2=-1(不合题意,舍去).(2)当x<0时,原方程化为x2+x-2=0,解得

来源:学生作业帮助网 编辑:作业帮 时间:2024/05/05 02:33:12
阅读下面例题:解方程x²-x的绝对值-2=0 (1)当x≥0时,原方程化为:x²-x的绝对值-2=0(1)当x≥0时,原方程化为x2-x-2=0,解得:x1=2,x2=-1(不合题意,舍去).(2)当x<0时,原方程化为x2+x-2=0,解得

阅读下面例题:解方程x²-x的绝对值-2=0 (1)当x≥0时,原方程化为:x²-x的绝对值-2=0(1)当x≥0时,原方程化为x2-x-2=0,解得:x1=2,x2=-1(不合题意,舍去).(2)当x<0时,原方程化为x2+x-2=0,解得
阅读下面例题:解方程x²-x的绝对值-2=0 (1)当x≥0时,原方程化为:x²-x的绝对值-2=0
(1)当x≥0时,原方程化为x2-x-2=0,解得:x1=2,x2=-1(不合题意,舍去).
(2)当x<0时,原方程化为x2+x-2=0,解得:x1=1(不合题意,舍去),x2=-2
∴原方程的根是x1=2,x2=-2.
请参照以上解法解方程x²+2(x的绝对值)-3=0

阅读下面例题:解方程x²-x的绝对值-2=0 (1)当x≥0时,原方程化为:x²-x的绝对值-2=0(1)当x≥0时,原方程化为x2-x-2=0,解得:x1=2,x2=-1(不合题意,舍去).(2)当x<0时,原方程化为x2+x-2=0,解得
当x大于0时 当x小于0时
2 2
x +2x+1=4 x -2x+1=4
x+1=+-2 x-1=-+2
x1=-3(舍去) x1=3(舍去)
x2=1 x2=-1