作业帮S(2m-1)=(2m-1)a1+(2m-1)(2m-2)d/2 =(2m-1)[a1+(m-1)d]等号后面的式子怎么化简得来的S(2m-1)=(2m-1)a1+(2m-1)(2m-2)d/2=(2m-1)[a1+(m-1)d]=am(2m-1)
来源：学生作业帮助网 编辑：作业帮 时间：2024/05/06 09:16:24
![S(2m-1)=(2m-1)a1+(2m-1)(2m-2)d/2 =(2m-1)[a1+(m-1)d]等号后面的式子怎么化简得来的S(2m-1)=(2m-1)a1+(2m-1)(2m-2)d/2=(2m-1)[a1+(m-1)d]=am(2m-1)](/uploads/image/z/14553754-34-4.jpg?t=S%282m-1%29%3D%282m-1%29a1%2B%282m-1%29%282m-2%29d%2F2+%3D%282m-1%29%5Ba1%2B%28m-1%29d%5D%E7%AD%89%E5%8F%B7%E5%90%8E%E9%9D%A2%E7%9A%84%E5%BC%8F%E5%AD%90%E6%80%8E%E4%B9%88%E5%8C%96%E7%AE%80%E5%BE%97%E6%9D%A5%E7%9A%84S%282m-1%29%3D%282m-1%29a1%2B%282m-1%29%282m-2%29d%2F2%3D%282m-1%29%5Ba1%2B%28m-1%29d%5D%3Dam%282m-1%29)
S(2m-1)=(2m-1)a1+(2m-1)(2m-2)d/2 =(2m-1)[a1+(m-1)d]等号后面的式子怎么化简得来的S(2m-1)=(2m-1)a1+(2m-1)(2m-2)d/2=(2m-1)[a1+(m-1)d]=am(2m-1)
S(2m-1)=(2m-1)a1+(2m-1)(2m-2)d/2 =(2m-1)[a1+(m-1)d]等号后面的式子怎么化简得来的
S(2m-1)=(2m-1)a1+(2m-1)(2m-2)d/2
=(2m-1)[a1+(m-1)d]=am(2m-1)
S(2m-1)=(2m-1)a1+(2m-1)(2m-2)d/2 =(2m-1)[a1+(m-1)d]等号后面的式子怎么化简得来的S(2m-1)=(2m-1)a1+(2m-1)(2m-2)d/2=(2m-1)[a1+(m-1)d]=am(2m-1)
S(2m-1)=(2m-1)a1+2(2m-1)(m-1)d/2 提取公因式
=(2m-1)[a1+(m-1)d]
再下面
这是个等差数列的公式am=a1+(m-1)d
所以就得到了结果(2m-1)am