m^2-n^2+n-1/4和a^4-3a^2-4

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m^2-n^2+n-1/4和a^4-3a^2-4

m^2-n^2+n-1/4和a^4-3a^2-4
m^2-n^2+n-1/4和a^4-3a^2-4

m^2-n^2+n-1/4和a^4-3a^2-4
题目不完整

1.原式=(4m^2-4n^2+4n-1)/4
=(4m^2-(2n-1)^2)/4
=(2m+2n-1)(2m-2n+1)/4
2.原式=a^4-4a^2+a^2-4
=a^2(a+2)(a-2)+(a+2)(a-2)
=(a^2+1)(a+2)(a-2)

m^2-n^2+n-1/4
=m^2-(n^2-n+1/4)
=m^2-(n-1/2)^2
=(m+n+1/2)(m-n+1/2)
a^4-3a^2-4
=(a^2-4)(a^2+1)
=(a+2)(a-2)(a^2+1)